Answer:
-6x⁷ + 12x − 3
Step-by-step explanation:
Method 1 :
[tex]-3x^0\ (2x^7-4x+1)[/tex]
[tex]= (-3x^0)\times 2x^7-(-3x^0)\times4x+(-3x^0)\times1[/tex]
[tex]= (-3x^0)\times 2x^7+(3x^0)\times4x+(-3x^0)\times1[/tex]
[tex]=-6x^{0+7}+12x^{0+1}-3x^0[/tex]
[tex]=-6x^{7}+12x^{1}-3x^0[/tex]
[tex]=-6x^{7}+12x-3[/tex]
Method 2 :
Note : x⁰ = 1
[tex]-3x^0\ (2x^7-4x+1)[/tex]
[tex]=-3\ (2x^7-4x+1)[/tex]
[tex]=-3\times2x^7-(-3)\times4x+(-3)\times1[/tex]
[tex]=-6x^7+12x-3[/tex]
