The 0.0080 hour have passed through the KCl.
given,
m = 1.18 kg
current I = 0.743 Amp/s
M.wt of potassium = 39.10 g
Moltan KCl
KCl → [tex]K^{+}[/tex] +[tex]Cl^{-}[/tex]
[tex]K^{+} +1e^{-}[/tex]→ K
n = 1 mole
m = M.wt x I x t/n x F
t = m x n x F/ M.wt x I
= 1.18 kg x 1 mole x 96000/ 39.10g x 0.743
= 29.0513/3600
= 0.0080 hour
Hence, the 0.0080 hour have passed through the KCl.
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