Answer:
86.2 m range
Explanation:
Vertical component of initial shot = 30 sin 55= 24.575 m/s
Now you can find out for how long it is in the air
when it hits the ground , position = 0
0 = 24.575 t - 1/2 ( 9.81) t ^2
finds t = 5.01 seconds (Using quadratic formula)
HORIZONTAL component = 30 cos 55 = 17.21 m/s
it travels this speed for 5.01 seconds
5.01 * 17.21 = 86.2 m
