notlafamosanex notlafamosanex
  • 17-09-2022
  • Mathematics
contestada

A polynomial p(x) is given as 2x^2-3kx+5
One of the zeros of p(x) is -1
Find k.

Respuesta :

profarouk profarouk
  • 17-09-2022

Answer:

[tex]k = -\frac{7}{3}[/tex]

Step-by-step explanation:

Given :

p(x) = 2x² − 3kx + 5

Since, -1 is a zero for p then :

p(-1) = 0

Solving the equation p(-1) = 0 for k :

p(-1) = 0

⇔ 2(-1)² − 3k(-1) + 5 = 0

⇔ 2 + 3k + 5 = 0

⇔ 3k = -5 - 2

⇔ 3k = -7

⇔ k = -7/3

NOTE :

If -1 is a zero of p

[tex]\Longrightarrow k = -\frac{7}{3}[/tex]

[tex]\Longrightarrow p(x) = 2x^2 - 3(\frac{-7}{3}) x + 5\\\Longrightarrow p(x) = 2x^2+ 7x + 5[/tex]

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