I don't know if u want this but ya :)
Solution:
Let f(x) = (x+3)^(1/3).
First, we have
lim_(x → -3) f(x) = (-3+3)^(1/3) = 0 = f(-3)
So f(x) is continuous at a = -3.
Next we have
lim_(h → 0) [f(-3+h) - f(-3)] / h
= lim_(h → 0) h^(1/3) / h
= lim_(h → 0) 1 / h^(2/3)
= infty
Since the limit does not exist, f(x) is not differentiable at a = -3.
Answer: D
