luxo
luxo
20-02-2017
Mathematics
contestada
cos b + sin b × tan b = sec b
Respuesta :
ChandrikaP
ChandrikaP
20-02-2017
cosb+sinb*tanb=secb
take LHS first
cosb+sinb*sinb/cosb----------
tanb=sinb/cosb
cosb+(sinb)^2/cosb
[cos^2b+sin^2b]/cosb
1/cosb=secb --------------
cos^2b+sin^2b=1
LHS=RHS
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