edrake1 edrake1

17-02-2015
Mathematics

contestada

Solve the quadratic equation y^2-5y=-4 by factoring.

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konrad509 konrad509

17-02-2015

[tex]y^2-5y=-4\\ y^2-5y+4=0\\ y^2-y-4y+4=0\\ y(y-1)+4(y-1)=0\\ (y+4)(y-1)=0\\ y=-4 \vee y=1 [/tex]

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