Respuesta :

luana
[tex] \left \{ {{-16x-9y=20} \atop {8x+2y=0\ \ | *2}} \right. \\\\ \left \{ {{-16x-9y=20} \atop {16x+4y=0}} \right. \\+------\\\\ -5y=20\ \ \ | divide\ by\ -5\\\\ y=-4\\\\ 16x=-4y\ \ \ | divide\ by\ 16\\\\ x=-\frac{1}{4}y=-\frac{1}{4}*(-4)=1[/tex]