hirajahangir
hirajahangir
16-03-2017
Mathematics
contestada
nCr/nPr=r!
give proof.
Respuesta :
LammettHash
LammettHash
16-03-2017
That's not true. If [tex]n\mathrm Cr[/tex] and [tex]n\mathrm Pr[/tex] are defined as
[tex]n\mathrm Cr=\dfrac{n!}{r!(n-r)!}[/tex]
[tex]n\mathrm Pr=\dfrac{n!}{(n-r)!}[/tex]
then
[tex]\dfrac{n\mathrm Cr}{n\mathrm Pr}=\dfrac{\frac{n!}{r!(n-r)!}}{\frac{n!}{(n-r)!}}=\dfrac1{r!}[/tex]
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