Respuesta :

apologiabiology
add 8 both sides
x²+4x+8=0
we can't factor this
we use quadratic formula
for ax²+bx+c=0
x=[tex] \frac{-b+/- \sqrt{b^2-4ac} }{2a} [/tex]
so
a=1
b=4
c=8

x=[tex] \frac{-4+/- \sqrt{4^2-4(1)(8)} }{2(1)} [/tex]
x=[tex] \frac{-4+/- \sqrt{-16} }{2} [/tex]
x=[tex] \frac{-4+/- 4i }{2} [/tex]
x=-2+/-2i

x=-2-2i and -2+2i


A is answer

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