an alpha particle (mass=6.6x10^-24g) emmited by a radium isotope travels at 3.4x10^7 mi/hr. what is its de broglie wavelength in meters

Respuesta :

We know that E = 0.5mv^2 = hc/(lambda), where lambda is the de broglie wavelength. E = 0.5mv^2 due to the speed that the alpha particle possess in the form of kinetic energy. Hope this helps!