nfjdbdbsbdh nfjdbdbsbdh
  • 18-04-2017
  • Mathematics
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13-6x=(2x-5)^2+3 what answer

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kaileighjsdfj kaileighjsdfj
  • 20-04-2017
13−6x=(2x−5)2+3Step 1: Simplify both sides of the equation.−6x+13=4x2−20x+28Step 2: Subtract 4x^2-20x+28 from both sides.−6x+13−(4x2−20x+28)=4x2−20x+28−(4x2−20x+28)−4x2+14x−15=0Step 3: Use quadratic formula with a=-4, b=14, c=-15.x=−b±√b2−4ac2ax=−(14)±√(14)2−4(−4)(−15)2(−4)x=−14±√−44−8
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