equilibrium constant of: O2(g)+2H2O(l)+2Sn2+(aq)→4OH−(aq)+2Sn4+(aq)

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abigirl08 abigirl08

19-04-2017
Chemistry

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equilibrium constant of: O2(g)+2H2O(l)+2Sn2+(aq)→4OH−(aq)+2Sn4+(aq)

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Аноним Аноним · Answer 1 · 2017-04-29T15:52:28+02:00

Аноним Аноним

29-04-2017

Equilibrium constant of a reaction is the ratio of the product of the concentration of the products in equilibrium over the product of the concentration of the reactants in equilibrium. For this case,

K = [OH]^4 [Sn4+]^2 / [O2] [H2O]^2[Sn2+]^2

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