PLEASEHELPONETIME
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  • 21-04-2017
  • Mathematics
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What are the solutions of the equation? x² – 12 = –4x

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irspow
irspow irspow
  • 21-04-2017
x^2+4x-12=0

x^2-2x+6x-12=0

x(x-2)+6(x-2)=0

(x-2)(x+6)=0

x=-6 and 2
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rorii
rorii rorii
  • 21-04-2017
x² – 12 = –4x
x² +4x– 12=0
(x+6)(x-2)=0
so 
x+6=0     or   x-2=0
x=-6                 x=2

(-6,2)
Answer Link

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