we know that
The area of a Kite is equal to
[tex]A=\frac{1}{2}(D1*D2)[/tex]
where
D1 and D2 are the diagonals of the kite
In this problem we have
[tex]A=51.68\ in^{2}[/tex]
[tex]D1=15.2\ in[/tex]
Substitute in the formula and solve for D2
[tex]51.68=\frac{1}{2}(15.2*D2)[/tex]
[tex]103.36=(15.2*D2)[/tex]
[tex]D2=103.36/15.2[/tex]
[tex]D2=6.8\ in[/tex]
therefore
the answer is the option B
[tex]6.8\ in[/tex]
