cassieratcliff cassieratcliff
  • 21-04-2017
  • Mathematics
contestada

solve the triangle B=71 degrees, b=15, c=8

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irspow
irspow irspow
  • 21-04-2017
sinC/8=sin71/15

sinC=8sin71/15

C=arcsin(8sin71/15)≈30.28°

A=180-71-arcsin(8sin71/15)≈78.72

a/sin78.72=15/sin71

a=15sin78.72/sin71≈15.56

So the angles and their opposite side lengths are:

A=78.72°, B=71, C=30.28°

a≈15.56, b=15, c=8


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