reilly2 reilly2
  • 16-05-2017
  • Mathematics
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Write 16x^2 + 25y^2 - 32x -159 =0
In standard form

Respuesta :

Аноним Аноним
  • 19-05-2017
[tex]16x^2 + 25y^2 - 32x -159 =0:x[/tex] 

Solve by using Quadratic Formula

[tex]x= \dfrac{-b+ \sqrt{b^2-4ac} }{2a}, \dfrac{-b- \sqrt{b^2-4ac} }{2a}[/tex] 

In this case, [tex]a=16[/tex],[tex] b=-32[/tex] and [tex]c=25{y}^{2}-159[/tex]

[tex]x= \dfrac{32+ \sqrt{(32)^2-4*16(25y^2-159)} }{2*16} ,}[/tex][tex]\dfrac{32- \sqrt{(32)^2-4*16(25y^2-159)} }{2*16}[/tex] 

[tex]x= \dfrac{32+40i \sqrt{y^2-7} }{32} , \dfrac{32-40i \sqrt{y^2-7} }{32} [/tex] 

[tex]x=1+ \dfrac{5i \sqrt{y^2-7} }{4} ,1- \dfrac{5i \sqrt{y^2-7} }{4} [/tex]
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