The distance between city A and city B is 22 miles. The distance between city B and city C is 54 miles. The distance between city A and city C is 51 miles.

What type of triangle is created by the three cities?

an acute triangle, because 222 + 542 >512
an acute triangle, because 222 + 512 >542
an obtuse triangle, because 222 + 542 >512
an obtuse triangle, because 222 + 512 >542

Respuesta :

square each side 
54^2 ,  51^2 and 22^2    which work out to be 

2916, 2601  and 484                ( 2601 + 484 =  3085)

now 2916 < 2601  + 484

 54^2 < 51^2 + 22^2 

or we can write this as
22^2 + 51^2 > 54^2      which is an acute angled triangle 

choice B is the correct one.