soup6 soup6
  • 17-06-2017
  • Mathematics
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Need help on this one plizz

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jdoe0001 jdoe0001
  • 17-06-2017
[tex]\bf n^{th}\textit{ term of a geometric sequence}\\\\ a_n=a_1\cdot r^{n-1}\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ r=\textit{common ratio}\\ ----------\\ n=9\\ a_1=1\\ r=-\frac{1}{3} \end{cases}\implies a_9=1\left( -\frac{1}{3} \right)^{9-1}[/tex]
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