TrucerZ2700 TrucerZ2700
  • 16-10-2017
  • Chemistry
contestada

A certain ore yields an average of 64​% iron. how much ore is needed to obtain 896 lb of​ iron?

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andriansp andriansp
  • 23-10-2017
In this case, the ore yield 64% iron and you need 896 lb of iron. From this description you can get an equation like this:

Iron= iron ore mass * 64%

Then, to get 896 of iron the calculation should be:
Iron= iron ore mass * 64%
896 lb= iron ore mass * 0.64
iron ore mass= 896 lb/ 0.64= 1400lb
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