Respuesta :

choixongdong
using x for the variablex = -2, x = 0, and x = 3
so x(x + 2)(x - 3) = 0
x(x^2 + 2x - 3x - 6) = 0
x(x^2 - x - 6) = 0
x^3 - x^2 - 6x = 0
answer
x^3 - x^2 - 6x = 0

hope it helps

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