ice|-9°c---->ice| 0°c ----> water|0°c u need the latent heat value of ice and the specific heat capacity of Ice SHC of ice = 2.108 kJ/kgK = 2108jkg-¹k-¹ latent heat of ice = 334j so you have H = mcΔ + mL H= [7×2108×9] + (7×334) H= 132804 + 2338 H= 135142 joules H = 0.135Mj
