otter7994
otter7994
17-11-2017
Mathematics
contestada
Need Algebra Help Please!
Respuesta :
choixongdong
choixongdong
17-11-2017
3^(4x-5) = (1/27)^(2x+10)
3^(4x-5) = (3^-3)^(2x+10)
3^(4x-5) = (3)^(-6x - 30)
4x- 5 = -6x - 30
10x = -25
x = - 5/2
or
x = -2.5
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