angelaalien13 angelaalien13

18-01-2018
Mathematics

contestada

PLEASE HELP WITH QUESTION! MARKING BRAINLIEST + POINTS GIVEN.

Find the cube roots of 125(cos 288° + i sin 288°).

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stevekimaz stevekimaz

18-01-2018

The simple answer (not using multiples of 2[tex] \pi [/tex] (360°)) is
[tex]= \sqrt[3]{125} ((cos( \frac{288}{3})) + isin(( \frac{288}{3}))) = 5(cos96 + isin96)[/tex]

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