Answer:
2 and -10.
Step-by-step explanation:
(x-2)(x+10)=13
[tex]x^{2} +10x-2x-20 =13[/tex]
[tex]x^{2} +8x-20 =13[/tex]
[tex]x1=\frac{-8+\sqrt[2]{64-4(-20)} }{2}[/tex]
[tex]x1=\frac{-8+\sqrt[2]{64+80} }{2}[/tex]
[tex]x1=\frac{-8+12 }{2}[/tex]
[tex]x1=2.[/tex]
[tex]x2=\frac{-8-\sqrt[2]{64-4(-20)} }{2}[/tex]
[tex]x2=\frac{-8-\sqrt[2]{64+80} }{2}[/tex]
[tex]x2=\frac{-8-12 }{2}[/tex]
[tex]x2=-10.[/tex]
