Respuesta :

Everest2017
pH = 3.83  =  - log [H+]  to base 10

So [H+] = 10^ -3.83  = 1.48 * 10^-4 moles

[H+]  [OH-] = 10^-14

So [OH-] = 6.756 * 10^-11 moles

So Salt formation will be :  6.756 * 10^-11 moles